Full-wave rectifier using center-tapped transformer — DC output & ripple
Vm = Vs × √2
Vdc = (2 × Vm) / π = 0.636 × Vm
Vdc_actual = Vdc − Vf (only one diode drop)
Ripple Vr ≈ Vdc / (2 × f × C × RL)
Efficiency = 81.2% | Ripple factor = 0.48 | Ripple freq = 2 × f
Advantage over bridge: only 1 diode drop. Disadvantage: needs center-tapped transformer (total secondary = 2×Vs).