Inductors

AC Circuits · 11 min read

A capacitor stores energy in an electric field between two plates. An inductor stores it in a magnetic field around a coil. The two components are duals of each other — every rule for one has a mirror-image rule for the other, and the AC behaviour of real circuits comes from mixing them.

Structure

At heart an inductor is just a coil of wire. Pass current through the NN turns and each turn contributes to a magnetic field that loops through the core and closes around the outside of the coil. Wrap the wire around a lump of ferromagnetic material (iron, ferrite) and the field strengthens dramatically.

iron / ferrite coreBSNII⊙ current out of page · ⊗ current into page · right-hand rule ⇒ thumb to N
Current through N turns of wire — ⊙ on top, ⊗ on bottom — generates a magnetic field that exits the right (N) pole, loops around through space, and re-enters on the left (S) pole. Inside the core the field points S→N; outside it closes the loop N→S (arrows).

Inductance and back-EMF

The total flux threading all N turns is the flux linkage Ψ=NBAΨ = NBA. For a given coil geometry, Ψ is proportional to the current through it — the constant of proportionality is the inductance LL:

Ψ=LI\Psi = L I

LL is measured in henries (H). One henry stores one weber of flux linkage per ampere of current. Real inductors span microhenries (RF chokes) through millihenries (audio inductors) up to henries (mains transformers and large chokes).

Change the current, and the flux changes with it. A changing flux induces an EMF by Faraday's law — the induced EMF opposes the change that caused it (Lenz's law):

v=LdIdtv = L \frac{dI}{dt}

That's the inductor's defining equation. Try to ramp current up quickly and the coil fights back with a big voltage. Try to hold current steady and it offers no resistance at all — just the DC resistance of the copper wire, which is usually tiny.

Energy storage

Building up current in an inductor requires work against the back-EMF; that work is stored in the magnetic field:

W=12LI2W = \tfrac{1}{2} L I^2

When the current eventually falls, that energy has to go somewhere — which is why switching inductive loads abruptly (a relay, a motor winding, an ignition coil) produces voltage spikes. The energy in 12LI2\tfrac{1}{2} L I^2 will find a path, inductive-spike kickback being the classic example. A flyback diode is the standard defence.

Inductors in series and parallel

Combine inductors and the rules mirror resistors (the opposite of capacitors):

Series:Leq=L1+L2+\text{Series:} \quad L_{eq} = L_1 + L_2 + \ldots
Parallel:1Leq=1L1+1L2+\text{Parallel:} \quad \frac{1}{L_{eq}} = \frac{1}{L_1} + \frac{1}{L_2} + \ldots
SeriesL_eq = L₁ + L₂L₁L₂Same current, voltages addParallel1/L_eq = 1/L₁ + 1/L₂L₁L₂Same voltage; I = I₁ + I₂
Inductor combination rules match resistor rules (opposite of caps): series adds, parallel uses the reciprocal formula.

Series — the same current flows through every coil, so the induced EMFs add up in the same direction. That's why the inductances add linearly (two 10 mH chokes in series = 20 mH).

Parallel — the coils share the same terminal voltage, so each one carries a current set by its own inductance via Ik=vdt/LkI_k = \int v \, dt / L_k. The total current is the sum of the branch currents, and dividing through gives the reciprocal-sum rule. Two 10 mH inductors in parallel = 5 mH.

Caveat: the parallel rule assumes the coils are magnetically isolated from each other. If they share a core, mutual inductance MM enters the formula — Leq=L1+L2±2ML_{eq} = L_1 + L_2 \pm 2M for series — and the problem gets richer. For this topic we assume no coupling.

Inductors: v=LdI/dtv = L \, dI/dt, energy 12LI2\tfrac{1}{2} L I^2, series adds, parallel reciprocates. The mirror image of capacitors in every respect.

Circuit application — flux linkage Ψ=LI\Psi = LI

The combination rules become concrete once you wire inductors into a real DC loop and trace what each coil stores. A current source forces a fixed supply current IsI_s into the network.

For series inductors, every coil carries the same current IsI_s. Each stores a flux linkage proportional to its own inductance:

Ψk=LkIs\Psi_k = L_k \, I_s

Larger L → more flux, same current. The total flux linkage of the pair equals LeqIsL_{eq} \, I_s with Leq=L1+L2L_{eq} = L_1 + L_2.

IsI →L₁Ψ₁ = L₁ · IL₂Ψ₂ = L₂ · ISame I — flux depends on L: Ψ₁ ≠ Ψ₂ if L₁ ≠ L₂
Series inductors share the same current I. Each contributes flux linkage Ψ = L × I in proportion to its own inductance.

For parallel inductors, the dual relationship holds: both coils develop the same flux linkage — just as parallel capacitors share the same voltage. The current, however, divides inversely with inductance (larger L draws less current):

Ik=IsLeqLkI_k = I_s \frac{L_{eq}}{L_k}

So Ψk=LkIk=LeqIs\Psi_k = L_k \, I_k = L_{eq} \, I_s for every branch — all equal. This is the pure dual of capacitors in series (where all caps carry the same charge).

IsL₁I₁ ↓L₂I₂ ↓I₁ + I₂ = I · Ψ₁ = Ψ₂ = L_eq × I (larger L → less I)
Parallel inductors share the same flux linkage Ψ — the dual of parallel capacitors sharing the same voltage. Current divides inversely with L: the larger inductor draws less current.

The stored energy per inductor follows from Wk=12LkIk2W_k = \tfrac{1}{2} L_k I_k^2. For parallel inductors the larger L draws less current, so it stores less energy despite being bigger — another counterintuitive dual of the capacitor case.

Duality table

Every property a capacitor has, an inductor has the dual of. Memorising the table below short-circuits a lot of AC analysis:

  • Capacitor stores energy in an electric field between plates; inductor stores it in a magnetic field around a coil.
  • Cap stores charge proportional to V: Q=CVQ = CV. Inductor stores flux linkage proportional to I: Ψ=LI\Psi = LI.
  • Cap current follows dV/dt: i=Cdv/dti = C \, dv/dt. Inductor voltage follows dI/dt: v=LdI/dtv = L \, dI/dt.
  • Caps block DC / pass AC. Inductors pass DC / block AC (or more precisely, block high-frequency AC — we'll make that precise with reactance in Topic 6).
  • Caps series-reciprocate, parallel-add. Inductors series-add, parallel-reciprocate.

Energising and de-energising

The duality from the table above carries straight into time-domain behaviour. A capacitor can't change its voltage instantly; an inductor, by the same token, can't change its current instantly — that would require infinite EMF across L. So when you close a switch on an L–R loop fed by a DC source VsV_s, the current ramps up rather than jumping.

The current rises exponentially from 0 toward its steady-state value Vs/RV_s / R:

i(t)=VsR(1et/τ)i(t) = \frac{V_s}{R} \left( 1 - e^{-t/\tau} \right)

The time constant is the dual of the RC version:

τ=LR\tau = \frac{L}{R}

With LL in henries and RR in ohms, τ\tau is again in seconds. A 1 H choke fed through 100 Ω has τ=10ms\tau = 10\,\text{ms}; a 10 µH inductor through 10 Ω is τ=1μs\tau = 1\,\mu\text{s}. The bigger the inductor, the slower it lets current change — large L resists fast di/dt by generating large opposing voltage.

The 63 % rule (again). At t=τt = \tau, the current has reached 0.632Vs/R\approx 0.632 \, V_s/R. By 5τ5\tau the inductor is effectively at full current. The shape and the 63 % / 5τ landmarks are identical to the RC case — only the variable (current here, voltage there) and the time constant formula change.

The voltage across the inductor walks the opposite direction: it starts at VsV_s (because vL=LdI/dtv_L = L \, dI/dt is largest when current is rising fastest) and decays toward zero as the current settles:

vL(t)=Vset/τv_L(t) = V_s \, e^{-t/\tau}

Energising shape — i rises toward V_s/R; inductor voltage decays as the current builds. Full interactive playground on the Simulate page.

Opening the switch is where inductors get spicy. The energy stored in the magnetic field — 12LI2\tfrac{1}{2} L I^2, from the energy section above — has to go somewhere. The inductor refuses to let current drop instantly; it generates whatever back-EMF is needed to keep current flowing through whatever path remains. In a clean L–R loop the current decays exponentially:

i(t)=I0et/τi(t) = I_0 \, e^{-t/\tau}

But if the path is broken — switch contacts opening across a real coil with no freewheel diode or snubber — the back-EMF can spike to hundreds or thousands of volts, arc across the contacts, and damage things. That's why every relay coil, motor winding, and solenoid you'll meet in industrial wiring has some kind of protection across it.

back-EMF

De-energising shape — i decays from I_0 = V_s/R; the back-EMF spike at t = 0 marks the polarity reversal across L.

Duality with capacitors, in motion. RC: voltage rises, current decays, τ=RC\tau = RC. LR: current rises, voltage decays, τ=L/R\tau = L/R. Same exponential, same 63 % / 5τ landmarks, swapped variables. Memorise one curve and you've memorised both.