Common Base, Common Gate & Cascode — Worked Example

Analog Electronics · Common Base, Common Gate & Cascode · Example

Designing a discrete cascode video amplifier

Scenario: A video signal chain needs Aᵥ = −50 V/V with bandwidth ≥ 50 MHz from a 50 Ω source. Use 2N3904 BJTs for both the CE and CB stages.

Device parameters: Cμ=4pFC_{\mu} = 4\,\text{pF}, β=200\beta = 200, VA=100VV_A = 100\,\text{V}, VCC=12VV_{CC} = 12\,\text{V}, IC=5mAI_C = 5\,\text{mA}.

  1. Spec — Aᵥ = −50 V/V, bandwidth ≥ 50 MHz, Rₛ = 50 Ω.

    Compute transconductance and output resistance at 5 mA:

    gm=ICVT=5mA25mV=200mA/Vg_m = \frac{I_C}{V_T} = \frac{5\,\text{mA}}{25\,\text{mV}} = 200\,\text{mA/V}
    ro=VAIC=100V5mA=20kΩr_o = \frac{V_A}{I_C} = \frac{100\,\text{V}}{5\,\text{mA}} = 20\,\text{k}\Omega

    For Aᵥ = −50, we need RC50/gm=250ΩR_C \approx 50 / g_m = 250\,\Omega.

  2. CE-alone bandwidth — fails the spec.

    With a single CE stage, the Miller effect multiplies Cμ by (1 + |Aᵥ|) = 51:

    Cin,Miller=Cμ(1+Av)=4pF×51=204pFC_{in,Miller} = C_{\mu} \cdot (1 + |A_v|) = 4\,\text{pF} \times 51 = 204\,\text{pF}
    f3dB,CE=12πRSCin,Miller=12π×50×204×101215.6MHzf_{3dB,CE} = \frac{1}{2\pi \cdot R_S \cdot C_{in,Miller}} = \frac{1}{2\pi \times 50 \times 204 \times 10^{-12}} \approx 15.6\,\text{MHz}

    15.6 MHz < 50 MHz — fails the spec. A single CE stage cannot meet the bandwidth requirement with this gain.

  3. Cascode design — stack a CB on top of the CE.

    The CB stage holds the CE collector at near-AC-ground, so Cμ is no longer multiplied:

    f3dB,cascode=12πRSCμ=12π×50×4×1012796MHzf_{3dB,cascode} = \frac{1}{2\pi \cdot R_S \cdot C_{\mu}} = \frac{1}{2\pi \times 50 \times 4 \times 10^{-12}} \approx 796\,\text{MHz}

    796 MHz ≫ 50 MHz — far exceeds the spec with ≈ 15× headroom before parasitic poles take over.

  4. Bias design — both stages share Iᴄ = 5 mA.

    The lower CE (Q1) is biased with a standard voltage-divider (R₁, R₂). Set VE,Q1 ≈ 1 V for stability: RE=VE/IC=1/5mA=200ΩR_E = V_E / I_C = 1 / 5\,\text{mA} = 200\,\Omega.

    The upper CB (Q2) base is biased so that Q2's emitter sits about 0.7 V above Q1's collector. If Q1's collector sits at ≈ 5 V, then:

    VB,Q2=VC,Q1+VBE,Q25+0.7=5.7VV_{B,Q2} = V_{C,Q1} + V_{BE,Q2} \approx 5 + 0.7 = 5.7\,\text{V}

    Set the RB3/RB4 divider to deliver 5.7 V. With VCC=12VV_{CC} = 12\,\text{V}: use RB3 = 6.8 kΩ, RB4 = 5.6 kΩ (standard E24 values give ≈ 5.65 V).

  5. Result — bandwidth and gain confirmed.
    AvgmRC=200mA/V×250Ω=50V/VA_v \approx -g_m \cdot R_C = -200\,\text{mA/V} \times 250\,\Omega = -50\,\text{V/V}\quad ✓
    f3dB796MHz(15\times above 50 MHz spec)f_{3dB} \approx 796\,\text{MHz}\quad \text{(15\times\ above 50 MHz spec)}\quad ✓

    The cascode delivers Aᵥ = −50 V/V at 5 mA with bandwidth headroom to ~800 MHz before parasitic poles (bond wires, package capacitance) take over. One extra transistor buys a 51× bandwidth win over the single CE stage.

Cascode is the standard fix when CE bandwidth disappoints — adds one transistor for a 50× bandwidth win. The 2N3904 cascode at 50 Ω source resistance can comfortably exceed 500 MHz, well into the video band.