Designing a discrete cascode video amplifier
Scenario: A video signal chain needs Aᵥ = −50 V/V with bandwidth ≥ 50 MHz from a 50 Ω source. Use 2N3904 BJTs for both the CE and CB stages.
Device parameters: Cμ=4pF, β=200, VA=100V, VCC=12V, IC=5mA.
- Spec — Aᵥ = −50 V/V, bandwidth ≥ 50 MHz, Rₛ = 50 Ω.
Compute transconductance and output resistance at 5 mA:
gm=VTIC=25mV5mA=200mA/V ro=ICVA=5mA100V=20kΩ For Aᵥ = −50, we need RC≈50/gm=250Ω.
- CE-alone bandwidth — fails the spec.
With a single CE stage, the Miller effect multiplies Cμ by (1 + |Aᵥ|) = 51:
Cin,Miller=Cμ⋅(1+∣Av∣)=4pF×51=204pF f3dB,CE=2π⋅RS⋅Cin,Miller1=2π×50×204×10−121≈15.6MHz 15.6 MHz < 50 MHz — fails the spec. A single CE stage cannot meet the bandwidth requirement with this gain.
- Cascode design — stack a CB on top of the CE.
The CB stage holds the CE collector at near-AC-ground, so Cμ is no longer multiplied:
f3dB,cascode=2π⋅RS⋅Cμ1=2π×50×4×10−121≈796MHz 796 MHz ≫ 50 MHz — far exceeds the spec with ≈ 15× headroom before parasitic poles take over.
- Bias design — both stages share Iᴄ = 5 mA.
The lower CE (Q1) is biased with a standard voltage-divider (R₁, R₂). Set VE,Q1 ≈ 1 V for stability: RE=VE/IC=1/5mA=200Ω.
The upper CB (Q2) base is biased so that Q2's emitter sits about 0.7 V above Q1's collector. If Q1's collector sits at ≈ 5 V, then:
VB,Q2=VC,Q1+VBE,Q2≈5+0.7=5.7V Set the RB3/RB4 divider to deliver 5.7 V. With VCC=12V: use RB3 = 6.8 kΩ, RB4 = 5.6 kΩ (standard E24 values give ≈ 5.65 V).
- Result — bandwidth and gain confirmed.
Av≈−gm⋅RC=−200mA/V×250Ω=−50V/V✓ f3dB≈796MHz(15\times above 50 MHz spec)✓ The cascode delivers Aᵥ = −50 V/V at 5 mA with bandwidth headroom to ~800 MHz before parasitic poles (bond wires, package capacitance) take over. One extra transistor buys a 51× bandwidth win over the single CE stage.
Cascode is the standard fix when CE bandwidth disappoints — adds one transistor for a 50× bandwidth win. The 2N3904 cascode at 50 Ω source resistance can comfortably exceed 500 MHz, well into the video band.